Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.1 - Rates of Change and Tangents to Curves - Exercises 2.1 - Page 46: 4

Answer

a.)$\frac{-2}{\pi}$ b.) 0

Work Step by Step

The definition of average rate of change is $\frac{f(x2) - f(x1)}{x2-x1}$. a.) g(t) = 2 + cos t interval = [0, $\pi$] $\frac{g(\pi) - g(0)}{\pi - 0}$. g($\pi$) = 2 + cos $\pi$ = 2-1 = 1 g(0) = 2 + cos(0) = 2 + 1 = 3 $\frac{1 -3}{\pi - 0}$. = $\frac{-2}{\pi}$ b.) g(t) = 2 + cos t interval = [-$\pi$, $\pi$] $\frac{g(\pi) - g(-\pi)}{\pi - (-\pi)}$. g($\pi$) = 2 + cos $\pi$ = 2-1 = 1 g(-$\pi$) = 2 + cos(-$\pi$) = 2 - 1 = 1 $\frac{1 -1}{\pi - (-\pi)}$. = $\frac{0}{2\pi}$ =0
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