Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Additional and Advanced Exercises - Page 103: 11

Answer

See explanations.

Work Step by Step

Step 1. Assume $\lim_{x\to c}f(x)=L_1$ and at the same time, $\lim_{x\to c}f(x)=L_2$ Step 2. Taking the difference of the above two limits, we have $L_1-L_2=\lim_{x\to c}f(x)- \lim_{x\to c}f(x)= \lim_{x\to c}(f(x)-f(x))=0$ Thus $L_1=L_2$
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