Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.4 - Double Integrals in Polar Form - Exercises 15.4 - Page 893: 29

Answer

12$\pi $

Work Step by Step

We calculate the area as follows: $ A=2\int^{\pi/6}_0 \int^{12cos3\theta}_0 rdrd\theta $ =$144\int^{\pi/6}_0 cos^23\theta d\theta $ =12$\pi $
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