Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.4 - Double Integrals in Polar Form - Exercises 15.4 - Page 893: 11


$2\pi $

Work Step by Step

$\int ^2_0 \int ^{\sqrt{1-y^2}}_0(x^2+y^2)dxdy $ =$\int ^{2\pi}_0 \int ^a_0 r dr d\theta $ =4 $\int ^{\pi/2}_0 d\theta $ =$2\pi $
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