Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.4 - Double Integrals in Polar Form - Exercises 15.4 - Page 893: 28



Work Step by Step

A=$2\int^{\pi/2}_0 \int ^{1+cos\theta}_1 rdr d\theta $ =$\int^{\pi/2}_0 (2cos\theta+cos^2\theta) d\theta $ =$\frac{8+\pi}{4}$
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