Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.1 - Double and Iterated Integrals over Rectangles - Exercises 15.1 - Page 875: 32

Answer

since the integral of the odd function x over an interval symmetric to 0 is equal to 0

Work Step by Step

$\int^{\frac{\pi}{2}}_{0} sin(\sqrt{y})dy$ is some number, say a then $\int^{1}_{-1} \int^{\frac{\pi}{2}}_{0} xsin\sqrt{y} =a \int^{1}_{-1}xdx=0$ since the integral of the odd function x over an interval symmetric to 0 is equal to 0
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