Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.1 - Double and Iterated Integrals over Rectangles - Exercises 15.1 - Page 875: 27



Work Step by Step

V=$\int\int f(x,y)dA$ =$\int^{1}_{0} \int^{1}_{0}(2-x-y)dy dx$ =$\int^{1}_{0}[2y-xy-\frac{1}{2}y^2]^1_0dx$ =$\int^{1}_{0}(\frac{3}{2}-x)dx$ =$[\frac{3}{2}x-\frac{1}{2}x^2]^1_0$ =1
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