Work Step by Step
$\int$1 to \ln8\int0 to \lny e^x+y =\int1 to \ln8(e^x+y)x=0 to x=y dy =\int1 to \ln8e^y(y-1)dy =[(y-1)\inte^ydy-\int(d(y-1)/dy)\inte^ydy)dy] =[(y-2)e^y]1 to ln8 =8ln8-16+e $
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