Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 14: Partial Derivatives - Section 14.4 - The Chain Rule - Exercises 14.4 - Page 817: 41


$-0.00005$ amp/s

Work Step by Step

As we know that $V=IR$ and $\dfrac{dV}{dt}=R\dfrac{dI}{dt}+I\dfrac{d R}{d t}$ Plug the given values respectively. $(-0.01)=(600)\dfrac{dI}{dt}+(0.04)(0.5)$ $\implies \dfrac{dI}{dt}=\dfrac{(-0.01)-(0.04)(0.5)}{600}$ Hence, $\dfrac{dI}{dt}=-0.00005$ amp/s
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