Answer
$\dfrac{4}{3}$
Work Step by Step
Consider $\dfrac{dy}{dx}=-\dfrac{F_x}{F_y}$
Plug the derivatives in equation the $\dfrac{dy}{dx}=-\dfrac{F_x}{F_y}$
This implies that $\dfrac{3x^2+y}{-4y+x} \times (-1)=\dfrac{-3x^2-y}{-4y+x} $
For point $(1,1)$, we have
$\dfrac{-3-1}{-4+1}=\dfrac{4}{3}$
