## Thomas' Calculus 13th Edition

$3.643\times 10^{11}\ J$
The work done by a constant force ${\bf F}$ acting through a displacement ${\bf D}=\vec{PQ}$ is ${\bf W}={\bf F}\cdot{\bf D}$ --- Defining a coordinate system with San Francisco at the origin, and Los Angeles on the positive x-axis, we have: ${\bf D}$=$\langle 605000\ m,\ 0\ m\rangle \quad {\bf F}=\langle 602148\ N,\ 0\ N\rangle$ ${\bf W}=(602148\ N)(605000\ m)+0(0)=3.643\times 10^{11}\ Nm$ $=3.643\times 10^{11}\ J$