#### Answer

$2x-3y=-8$

#### Work Step by Step

The result of exercise 31 tells us that ${\bf v}=a{\bf i} + b{\bf j}$
is perpendicular to the lines $ax+by=c$
Here, ${\bf v}=2\cdot{\bf i} + (-3)\cdot{\bf j}$,
and the lines are $2x-3y=c.$
$P(11,10)$ is on the line $\Rightarrow \left\{\begin{array}{l}
2(11)-3(10)=c\\
c=-8
\end{array}\right.$
so the line equation is $\quad 2x-3y=-8$
(a second point on the line is $(-4,0)$ )