Answer
$2x+7y+2z=-10$
Work Step by Step
The normal equation of plane is given as: $ n=\lt 2,7,2 \gt$
Consider the standard equation of plane passing through the point $(x_1,y_1,z_1)$ be $a(x-x_1)+b(y-y_1)+c(z-z_1)=0$
and for point $(-2,0,-3)$, we get
$2(x+2)+7(y-0)+2(z+3)=0 \implies 2x+4+7y+2z+6=0$
Thus, $2x+7y+2z=-10$
