Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Practice Exercises - Page 735: 56


$59.5^{ \circ}$

Work Step by Step

The the angle between vectors $v$ and $x$-axis is given as: $ \theta = \cos ^{-1} (\dfrac{v_x}{|v|})$ Here, $v=\lt 3,-5,1 \gt$ $|v|=\sqrt{3^2+(-5)^2+(1)^2}= \sqrt {35}$ Thus, $ \theta = \cos ^{-1} (\dfrac{3}{ \sqrt {35}})=59.5^{ \circ}$
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