Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Practice Exercises - Page 735: 51


$\lt 0,-3,3 \gt$

Work Step by Step

Here, $n=\lt 2,1,-1 \gt $ and $v=\lt 1,1,1 \gt$ Now, the cross product of two vectors is: $n \times v=i(-1+1)-j(2+1)+k(2+1)=-3j+3k$ Therefore, the answer is: $\lt 0,-3,3 \gt$
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