## Thomas' Calculus 13th Edition

$\lt 0,-3,3 \gt$
Here, $n=\lt 2,1,-1 \gt$ and $v=\lt 1,1,1 \gt$ Now, the cross product of two vectors is: $n \times v=i(-1+1)-j(2+1)+k(2+1)=-3j+3k$ Therefore, the answer is: $\lt 0,-3,3 \gt$