Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.5 - Absolute Convergence; The Ratio and Root Tests - Exercises 10.5 - Page 598: 52

Answer

Diverges

Work Step by Step

We are given $a_{n+1} = \frac{n+\ln(n)}{n+10} \times a_n$ and $a_1 = \frac{1}{2}$ and $n=1,2,3,...,n$ Find the first few elements of the sequence : $a_{1+1} = \frac{1+\ln(1)}{1+10} \times \frac{1}{2} \Rightarrow a_2 = \frac{1}{22}$ for $a_{2+1}$ our $a_n = \frac{1}{22} \Rightarrow a_3 = \frac{2+\ln(2)}{2+10}\times\frac{1}{22} \Rightarrow a_3 = \frac{2+ln(2)}{264}$ for $a_3+1$ our $a_n = \frac{2+\ln(2)}{264} \Rightarrow $ we see that our ${a_n}$ is growing, then $a_{n+1}$ also growing Then, $\lim\limits_{n \to \infty} \frac{n+\ln(n)}{n+10} \times a_n = \infty $ and $\ne 0$, so the series $diverges$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.