Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.5 - Absolute Convergence; The Ratio and Root Tests - Exercises 10.5 - Page 598: 25

Answer

Diverges

Work Step by Step

Let us consider $\lim\limits_{n \to \infty} a_n=\lim\limits_{n \to \infty} (1-\dfrac{3}{n})^n$ This can be written as: $\lim\limits_{n \to \infty} a_n=\lim\limits_{n \to \infty} (1+(-\dfrac{3}{n}))^n$ $\implies \lim\limits_{n \to \infty} a_n=e^{-3}=\dfrac{1}{e^3}$ Therefore, $\lim\limits_{n \to \infty} a_n \ne 0$ Thus, the Series diverges and $\lim\limits_{n \to \infty} a_n=\dfrac{1}{e^3}$
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