Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.2 - Infinite Series - Exercises 10.2 - Page 580: 76

Answer

converges to $\dfrac{2}{x-1}$ for all $|\dfrac{3-x}{2}| \lt 1$ or, $1 \lt x \lt 5$

Work Step by Step

Formula to calculate the sum of a geometric series is: $S=\dfrac{a}{1-r}$; Here, $a=1$ and common ratio $r =\dfrac{3-x}{2}$ $S=\dfrac{1}{1-(\dfrac{3-x}{2})}$ or, $S=\dfrac{2}{x-1}$ Hence, the series converges to $\dfrac{2}{x-1}$ for all $|\dfrac{3-x}{2}| \lt 1$ or, $1 \lt x \lt 5$
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