Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 572: 148

Answer

n = 59

Work Step by Step

As the value of n changes , so as the value of $a_{n}$ changes. By putting the values , you will get to know that $a_{n}$ increases from 0.052 to $1.23 \times 10^{29}$ and then decreases to zero. So the sequence an converges to zero. The limit is L = 0. When n=58 $|a_{n}-L| = 0.0135 > 0.01 $ when n=59 $|a_{n}-L| = 0.0014 < 0.01 $ So, n = 59.
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