Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Practice Exercises - Page 636: 54



Work Step by Step

Consider the Maclaurin Series for $\cos x$ as follows: $ \cos x=\Sigma_{n=0}^\infty \dfrac{(-1)^n x^{2n}}{(2n)!}=1-\dfrac{1}{2!}x^2+\dfrac{1}{4!}x^4-...$ As we are given that $x=\dfrac{\pi}{3}$ Then, we have $\cos (x)=\cos (\dfrac{\pi}{3})=\dfrac{1}{2}$
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