Answer
$\sqrt 7$
Work Step by Step
Apply the cosines law $ c^2=a^2+b^2-2ab\cdot cosC $ We have
$ c^2=2^2+3^2-2\times2\times3cos60^\circ=7$ and $ c=\sqrt 7$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 28: 59
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