Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 28: 50

Answer

$\frac{1}{4}(2+\sqrt 2)$

Work Step by Step

$ sin^2\frac{3\pi}{8}=\frac{1}{2}(1-cos\frac{3\pi}{4})=\frac{1}{2}(1+\frac{\sqrt 2}{2})=\frac{1}{4}(2+\sqrt 2)$
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