Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.3 - Trigonometric Functions - Exercises 1.3 - Page 28: 51

Answer

$\frac{\pi}{3},\frac{2\pi}{3},\frac{4\pi}{3},\frac{5\pi}{3}$

Work Step by Step

From $ sin^2\theta=\frac{3}{4}$, we have $ sin\theta=\frac{\sqrt 3}{2}$ or $ sin\theta=-\frac{\sqrt 3}{2}$. Within $[0,2\pi]$, the answers for the above are: $\theta=\frac{\pi}{3},\frac{2\pi}{3},\frac{4\pi}{3},\frac{5\pi}{3}$
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