Answer
The exterior of a circle centered at the origin, with radius $\sqrt{7}$.
Work Step by Step
The plane is divided into two regions by the graph of
$x^{2}+y^{2}=7$
which is a circle centered at the origin, with radius $\sqrt{7}$.
The two regions are the interior and the exterior of the circle.
Testing (0,0) by inserting its coordinates into the inequality,
$0+0 \gt 7\qquad $ ... (false)
we see that the center does not belong to the solution set.
The curve itself is not included, as the inequality is strict.
The region represented by the inequality:
The exterior of a circle centered at the origin, with radius $\sqrt{7}$.
