Answer
$210$
Work Step by Step
The number of ordered sequences of three items chosen from seven equals to the number of permutations of 7 items taken 3 at a time : $P(7,3)=\frac{7!}{(7-3)!}=\frac{7!}{4!}=\frac{7*6*5*4*3*2*1}{4*3*2*1}=7*6*5=210$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 6 - Section 6.4 - Permutations and Combinations - Exercises - Page 437: 18
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