Answer
$4,950$
Work Step by Step
The number of combinations of 100 items taken 98 at a time :
$C(100,98)=\frac{100!}{98!(100-98)!}=\frac{100!}{98!*2!}=\frac{100*99*98*97*...*3*2*1}{98*97*96*,,,*2*1*2*1}=\frac{100*99}{2}=50*99=4,950$
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