Answer
$45$
Work Step by Step
The number of combinations of 10 items taken 8 at a time :
$C(10,8)=\frac{10!}{8!(10-8)!}=\frac{10!}{8!*2!}=\frac{10*9*8*7*6*5*4*3*2*1}{8*7*6*5*4*3*2*1*2*1}=\frac{10*9}{2}=5*9=45$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 6 - Section 6.4 - Permutations and Combinations - Exercises - Page 437: 11
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