Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 6 - Section 6.4 - Permutations and Combinations - Exercises - Page 437: 13

Answer

$20$

Work Step by Step

The number of combinations of 20 items taken 1 at a time : $C(20,1)=\frac{20!}{1!(20-1)!}=\frac{20!}{1!*19!}=\frac{20*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1}{1*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1}=20$
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