#### Answer

$( 0,-2)$

#### Work Step by Step

Remove the fractions by multiplying
the first equation with 6,
the second with 4
(common denominators).
$\left\{\begin{array}{llll}
2x & -3y & =6 & \\
x & +4y & =-8 & /\times(-2)
\end{array}\right.$
... we aim to eliminate x...
$\left\{\begin{array}{llll}
2x & -3y & =6 & \\
-2x & -8y & =16 & /\times(-2)
\end{array}\right.$
... add and solve ...
$-11y=22\qquad/\div(-11)$
$y=-2$
Back substitute into one of the above equations:
$x+4y=-8$
$x+4(-2)=-8\qquad/+8$
$x=0$
Solutions are ordered pairs (x,y):
$( 0,-2)$
Check graphically by graphing both lines in the same window and determining the intersection (see image).