## Finite Math and Applied Calculus (6th Edition)

$(2,2)$
Adding the two equations will eliminate y. The resulting equation: $2x=4\qquad/\div 2$ $x=2$ Back substitute into one of the initial equations: $x-y=0$ $2-y=0\quad/+y$ $2=y.$ Solutions are ordered pairs (x,y): $(2,2)$ Check graphically by graphing both lines in the same window and determining the intersection (see image).