#### Answer

$(3,1)$

#### Work Step by Step

Adding the two equations will eliminate y.
The resulting equation:
$2x=6\qquad/\div 2$
$x=3$
Back substitute into one of the initial equations:
$x+y=4$
$3+y=4\quad/-3$
$y=1.$
Solutions are ordered pairs (x,y):
$(3,1)$
Check graphically by graphing both lines in the same window and determining the intersection (see image).