Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 13 - Section 13.1 - The Indefinite Integral - Exercises - Page 961: 91

Answer

The first term $\displaystyle \int 2x^6\ \ $ makes no sense: no $dx$, and there shouldn't be an integral sign anyway. Correct answer:$\qquad 2x^{6}+-2x^{2}+C$

Work Step by Step

$\displaystyle \int(12x^{5}-4x)dx=12\int x^{5}dx-4\int xdx$ Term by term: $12\displaystyle \int x^{5}dx=12\cdot\frac{x^{6}}{6}+C=2x^{6}+C$ The first term $\displaystyle \int 2x^6$ makes no sense: no $dx$, and there shouldn't be an integral sign anyway. $-4\displaystyle \int xdx=-4\cdot\frac{x^{2}}{2}+C=-2x^{2}+C$ The last two terms are correct. Correct answer:$\qquad 2x^{6}+-2x^{2}+C$
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