Chapter 13 - Section 13.1 - The Indefinite Integral - Exercises - Page 961: 89

The integral $\displaystyle \int 1dx$ is incorrect; should be $x+C, ($not $1+C)$ Correct answer:$\displaystyle \qquad \frac{3x^{2}}{2}+x+C$

$\displaystyle \int(3x+1)dx=3\int xdx+\int 1dx$ The integral $\ \ \ \displaystyle 3\int xdx$ is correct, $\ \ ( \displaystyle \frac{3x^{2}}{2}+C)$ The integral $\displaystyle \int 1dx$ is incorrect; should be $x+C, ($not $1+C)$ Correct answer:$\displaystyle \qquad \frac{3x^{2}}{2}+x+C$