Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 12 - Section 12.6 - Elasticity - Exercises - Page 931: 5a

Answer

$E=-(-4p+33))\times\frac{p}{-2p^2+33p} = \frac{4p^2-33p}{-2p^2+33p}$

Work Step by Step

The demand function is $q=-2p^2+33p$ where ($9\leq p \leq 15$) The elasticity can be calculated as: $E=-\frac{dq}{dp}\times\frac{p}{q}$ The derivative of the demand function is :$\frac{dq}{dp}=-2\times2p+33=4p+33$ Therefore $E=-(-4p+33))\times\frac{p}{-2p^2+33p} = \frac{4p^2-33p}{-2p^2+33p}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.