Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 12 - Section 12.6 - Elasticity - Exercises - Page 931: 1

Answer

$E=1.5$ $p=\$25$ Revenue: $p\times q=25\times (1000-20\times25)=12,500$

Work Step by Step

If the demand function is $q=1000-20p$ and $p=\$30$ The elasticity can be calculated as: $E=-\frac{dq}{dp}\times\frac{p}{q}$ The derivative of the demand function is :$\frac{dq}{dp}=-20$ Therefore at the given price $E=-(-20)\times\frac{30}{1000-20\times30}=1.5$ The maximum revenue is at the price, where $E=1$ $E=20\times\frac{p}{1000-20\times p}=1$ $40p=1000$ $p=\$25$ Here, the revenue is $p\times q=25\times (1000-20\times25)=12,500$
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