Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 12 - Section 12.6 - Elasticity - Exercises - Page 932: 5b

Answer

$E=\frac{4\times10^2-33\times10}{-2\times10^2+33\times10}=\frac{70}{130}$ The demand is quite inelastic, as $0

Work Step by Step

As the elacticity is: $E=\frac{4p^2-33p}{-2p^2+33p}$, if $p=\$10$, then $E=\frac{4\times10^2-33\times10}{-2\times10^2+33\times10}=\frac{70}{130}$ The demand is quite inelastic, as $0
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