Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 12 - Section 12.3 - Higher Order Derivatives: Acceleration and Concavity - Exercises - Page 902: 32

Answer

Inflection points of $f(x)$ at $ x=0$ and $x=1.$

Work Step by Step

A curve is concave up if its slope is increasing, in which case the second derivative is positive. A curve is concave down if its slope is decreasing, in which case the second derivative is negative. A point in the domain of $f$ where the graph of $f$ changes concavity, from concave up to concave down or vice versa, is called a point of inflection. At a point of inflection, the second derivative is either zero or undefined. --- Points where $f''$ crosses the axis (changes signs): $\quad$ at $x=0.$ Points where its graph is broken: positive on one side of the break and negative on the other:$\quad x=1$ Inflection point of $f(x)$ at $ x=0$ and $x=1.$
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