Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 12 - Section 12.3 - Higher Order Derivatives: Acceleration and Concavity - Exercises - Page 902: 18

Answer

$(-1,1)$

Work Step by Step

A curve is concave up if its slope is increasing, in which case the second derivative is positive. A curve is concave down if its slope is decreasing, in which case the second derivative is negative. A point in the domain of $f$ where the graph of $f$ changes concavity, from concave up to concave down or vice versa, is called a point of inflection. At a point of inflection, the second derivative is either zero or undefined. ---- Observing from left to right, $(-\infty,-2)\quad$ slope positive, decreasing (concave down) $ x=-2\quad$ local maximum, slope becoming negative, (decreasing: concave down) $(-2,-1)\quad$ slope negative, decreasing (still concave down) $ x=-1\quad$ slope negative, but becoming less negative, increases, (change of concavity) $(-1,0)\quad$ slope negative, increasing to zero (concave up) $x=0\quad$ local minimum, slope becoming positive (still increasing, concave up) $(0,+\infty)\quad$ slope positive, continues increasing, (concave up). Change of concavity at $x=-1$. Inflection point: $(-1,1)$
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