Answer
$(3x+2) (8x-5) (\dfrac{3}{3x+2}+\dfrac{8}{8x-5})$
Work Step by Step
We have: $y=(3x+2) (8x-5)$
We differentiate both sides with respect to $x$.
$\ln y=\ln (3x+2)+\ln (8x-5) \\ \dfrac{1}{y} \dfrac{dy}{dx}=\dfrac{3}{3x+2}+\dfrac{8}{8x-5}\\ \dfrac{dy}{dx}=y (\dfrac{3}{3x+2}+\dfrac{8}{8x-5})\\ \dfrac{dy}{dx}=(3x+2) (8x-5) (\dfrac{3}{3x+2}+\dfrac{8}{8x-5})$
