Answer
$1.1(x^{2.1}-x)(3.4-x^{-2.1})+ (1.1x+4)(2.1x^{1.1}-1)(3.4-x^{-2.1})+(1.1x+4)(x^{2.1}-x)\cdot 2.1x^{-3.1}$
Work Step by Step
Using the more general product rule (example 1b),
$(f\cdot g\cdot h)^{\prime}=f^{\prime}gh+fg^{\prime}h+fgh^{\prime}$
$f(x)=1.1x+4,\qquad f^{\prime}(x)=1.1$
$g(x)=x^{2.1}-x,\qquad g^{\prime}(x)=2.1x^{1.1}-1$
$h(x)=3.4-x^{-2.1},\qquad $
$h^{\prime}(x)=-(-2.1x^{-3.1})=2.1x^{-3.1}$
$\displaystyle \frac{dy}{dx}=(f\cdot g\cdot h)^{\prime}(x)=$
$=1.1(x^{2.1}-x)(3.4-x^{-2.1})+ (1.1x+4)(2.1x^{1.1}-1)(3.4-x^{-2.1})+(1.1x+4)(x^{2.1}-x)\cdot 2.1x^{-3.1}$
... we do not need to expand the answer