Answer
$$\frac{5}{2}x\sqrt[3] x $$
Work Step by Step
$$\eqalign{
& {x^2}\sqrt x \cr
& {x^2}{x^{1/2}} \cr
& {\text{Multiply, recall that }}{x^m}{x^n} = {x^{m + n}} \cr
& {x^{2 + 1/2}} \cr
& {x^{5/2}} \cr
& {\text{Differentiate}} \cr
& \frac{d}{{dx}}\left[ {{x^{5/2}}} \right] \cr
& = \frac{5}{2}{x^{5/2 - 1}} \cr
& = \frac{5}{2}{x^{3/2}} \cr
& = \frac{5}{2}x\sqrt[3] x \cr} $$