Answer
$\displaystyle \frac{dy}{dx}=8x+12$
Work Step by Step
$f(x)=2x+3\ \ \quad g(x)=2x+3$
$f^{\prime}(x)=2\qquad g^{\prime}(x)=2$
$\displaystyle \frac{dy}{dx}=\frac{d}{dx}[f(x)g(x)]$= ... product rule ...
$= f^{\prime}(x)g(x)+f(x)g^{\prime}(x)$
$=2(2x+3)+2(2x+3)$
$=4(2x+3)$
$=8x+12$
