Answer
$\displaystyle \frac{dy}{dx}=32x-8$
Work Step by Step
$f(x)=4x-1\ \ \quad g(x)=4x-1$
$f^{\prime}(x)=4\qquad g^{\prime}(x)=4$
$\displaystyle \frac{dy}{dx}=\frac{d}{dx}[f(x)g(x)]$= ... product rule ...
$= f^{\prime}(x)g(x)+f(x)g^{\prime}(x)$
$=4(4x-1)+4(4x-1)$
$=8(4x-1)$
$=32x-8$
