Answer
$ 2+\displaystyle \frac{1}{x^{2}}$
Work Step by Step
Written in exponential form,
... sum/difference rule...
$f^{\prime}(x)=\displaystyle \frac{d}{dx}[2x]-\frac{d}{dx}[x^{-1}]$
... constant multiple ...
$=2\displaystyle \frac{d}{dx}[x]-\frac{d}{dx}[x^{-1}]$
... power rule...
$=2(1)-(-x^{-2})$
$=2+\displaystyle \frac{1}{x^{2}}$
