Answer
$20x(x^2-1)^{9} $
Work Step by Step
We have: $f(x)=(x^2-1)^{10}$
We differentiate both sides with respect to $x$.
$f^{\prime}(x)=\dfrac{d}{dx} [(x^2-1)^{10}] \\=(10) (x^2-1)^{10-1}\dfrac{d}{dx}(x^2-1)\\=10(x^2-1)^{9}\times 2x $
Simplify to obtain:
$f^{\prime}(x)=20x(x^2-1)^{9} $
