## Finite Math and Applied Calculus (6th Edition)

x=$-\frac{1}{2}$ or $x=-\frac{2}{3}$
$6x^{2}+13x+6$ =$6x^{2}+9x+4x+6$ =$3x(2x+1)+2(2x+1)$ =$(2x+1)(3x+2)$ x=$-\frac{1}{2}$ or $x=-\frac{2}{3}$