Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole

Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 40

Answer

$y=3$ or $y=-\frac{1}{3}$

Work Step by Step

$3y^{2}-8y-3$ =$3y^{2} - 9y + y -3$ =$3y(y-3)+1(y-3)$ $(y-3)(3y+1)$$=0$ $y=3$ or $y=-\frac{1}{3}$

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