Answer
y=$\frac{x}{2}$
Work Step by Step
$4y^{2}-4xy+x^{2}$
=$4y^{2}-2xy-2xy+x^{2}$
=$2y(2y-x)-x(2y-x)$
$(2y-x)(2y-x)$$=0$
$(2y-x)^{2}$$=0$
y=$\frac{x}{2}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 46
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