Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 10



Work Step by Step

$(3x+1)^{2}$ 1. Square the first term. $(3x)^{2} = 9x^{2}$ 2. Multiply the first term and second term inside the bracket together. Then multiply this answer by 2. So $(3x)(1)(2)=6x$ 3. Square the last term inside the bracket. $(1)^{2} =1$ 4. Add all your answers from steps 1-4 to get $9x^{2}+6x+1$.
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