Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.5 Inequalities - R.5 Exercises - Page R-21: 43

Answer

The solution is $(-5,3)$

Work Step by Step

$\frac{m-3}{m+5}\leq0$ First solve the corresponding equation $\frac{m-3}{m+5} = 0$ $m-3=0$ $m=3$ For $(-\infty,-5)$, choose $-6: \frac{-6-3}{-6+5}=9\gt0$ For $(-5,3)$, choose $0: \frac{0-3}{0+5}=\frac{-3}{5}\leq0$ For $(3,\infty)$, choose $5: \frac{5-3}{5+5}=\frac{1}{5}\gt0$ The solution is $(-5,3)$
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